What is the probability that AaBbCc X AaBbCc will produce an individual that is homozygous reccessive?
Using the multiplication rule you take the probabilities of each individual event and multiply them together. There is a 1/4 chance of aa, 1/4 of bb and 1/4 chance of cc, multiplied together this equals 1/64.
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1 comment:
hi,very useful. i am able to answer my trihybrid exam tomorrow. Thank you!
lhiz.
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