Tuesday, December 9, 2008

Classical Genetics

Today students turned in their projects on meiosis and non-disjunction disorders. Today students learned how to solve trihybrid crosses using the multiplication rule.

What is the probability that AaBbCc X AaBbCc will produce an individual that is homozygous reccessive?

One option for solving a trihybrid cross is to make a giant punnett square (see below) or you can the multiplication rule.

Using the multiplication rule you take the probabilities of each individual event and multiply them together. There is a 1/4 chance of aa, 1/4 of bb and 1/4 chance of cc, multiplied together this equals 1/64.

Click here for practice genetics problems.

1 comment:

Anonymous said...

hi,very useful. i am able to answer my trihybrid exam tomorrow. Thank you!
lhiz.